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Scorpion4ik [409]

3 years ago

9

isabella and jorge are placing markers along a cross-country running route. They need to place the 1st marker 50m from the start

and place the other 50m to the end of the 2km route.

1 answer:

DochEvi [55]3 years ago

4 0

Answer:

<h3>102Km route I think</h3>

Step-by-step explanation:

i hope it helps :)

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Ms. Spencer is packing orders for her bath supply business. One customer ordered 8 bath fizzies and 4 jars of sugar scrub. Each

sergey [27]

8 bath fizzes * 5 (ounces) = 40 ounces. 4 jars of sugar scrub * 1.5 (pounds) = 6 pounds. So 6 pound and 40 ounces. (40 ounces = 2.5 pounds. So 8.5 pounds in total.) ( If you want to convert the answer to ounces, 8.5 pounds is 136 ounces.)

8 0

3 years ago

In the equation Y = 8x+ 5 the name for y are

VLD [36.1K]

Answer:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

4 0

3 years ago

Need help for question 8 and 9. I need the equation that’s passes through the points!

dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = $\frac{y_2-y_1}{x_2-x_1}$

For two points (1, 4) and (5, 8),

m = $\frac{8-4}{5-1}$

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = $\frac{y_2-y_1}{x_2-x_1}$

For two points (2, 10) and (6, 4)

m = $\frac{10-4}{2-6}$

m = $-\frac{3}{2}$

By substituting the value of 'm' in the equation,

y = $-\frac{3}{2}x+b$

Since, this line passes through (2, 10)

10 = $-\frac{3}{2}(2)+b$

b = 10 + 2

b = 12

Therefore, equation of the line will be,

$y=-\frac{3}{2}x+12$

4 0

3 years ago

Due tomarrow please help!!!!!!!!!!!!!!!!!!!!!!!!! Identify the independent and dependent variables in the following statement.

BlackZzzverrR [31]

The independent variable is the variable that is being changed. In this statement, it would be water flowing flowing in the pool. The dependent variable is what is being changed so that would be the depth of the water.

There, I hope this helps! :)

6 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%3Dky" id="TexFormula1" title=" \frac{dy}{dt} =ky" alt=" \frac

sladkih [1.3K]

This ODE is separable; we have

$\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides gives a general solution of

$\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}$

B is the only choice that is applicable.

4 0

3 years ago