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2 years ago

Kyasis travels at 55mph. How many miles will she travel in 4 hours?

Mathematics

1 answer:

xxMikexx [17]2 years ago

6 0

Answer: 220 miles

Step-by-step explanation: If she travels 55 miles per hour, for four hours, then you need to do 55 times 4. The answer is 220.

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Please help me. look at the picture.

Butoxors [25]

It’s 0.775x +2.5 =correct

6 0

2 years ago

The area of a square is 15.1 units². Estimate the length of the sides. Explain how you estimated.

kykrilka [37]

If it is just an estimate then it would be around <em>4</em>. 15.1 is pretty close to 16 which has a perfect square root of 4. Since it is a square both length and width would be the same. To check it you can just square 4 or 4 times 4 and get 16. Hopefully I helped! And sorry if I am wrong.

BTW the exact answer would be 3.88~ (square root of 15.1) just incase you needed that. :)

6 0

2 years ago

If the given sequence is a geometric sequence, find the common ratio.

Tcecarenko [31]

Answer:

d. 1/4

Step-by-step explanation:

The ratio of adjacent terms is the common ratio:

(3/12)/(3/3) = 3/12 = 1/4

3 0

3 years ago

The value of a boat if depreciating at at a rate of 9% per year. In 2006 the boat was worth $17,800. Find the worth of the boat

svetlana [45]

Answer:

The worth of boat in 2013 will be $9202.6

Step-by-step explanation:

Rate of depreciation = 9% = 0.09

Cost of Boat in 2006 =$ 17,800

Cost of Boat in 2013 = ?

Years = 2013-2006= 7 years

The formula used is: $\mathbf{A=P(1+r)^{t}}$

Since the value of boat is depreciating the value of r will be r=-0.09

Here P = 17,800 , r=-0.09 and t = 7 years Finding A

$A=P(1+r)^{t}\\A=17,800(1+(-0.09))^7\\A=17,800(0.91)^7\\A=17,800(0.517)\\A=9202.6$

So, the worth of boat in 2013 will be $9202.6

4 0

2 years ago

Historically, the proportion of students entering a university who finished in 4 years or less was 63%. To test whether this pro

Neporo4naja [7]

Answer:

z(c) = - 1,64

We reject the null hypothesis

Step-by-step explanation:

We need to solve a proportion test ( one tail-test ) left test

Normal distribution

p₀ = 63 %

proportion size p = 51 %

sample size n = 114

At 5% level of significance α = 0,05, and with this value we find in z- table z score of z(c) = 1,64 ( critical value )

Test of proportion:

H₀ Null Hypothesis p = p₀

Hₐ Alternate Hypothesis p < p₀

We now compute z(s) as:

z(s) = ( p - p₀ ) / √ p₀q₀/n

z(s) =( 0,51 - 0,63) / √0,63*0,37/114

z(s) = - 0,12 / 0,045

z(s) = - 2,66

We compare z(s) and z(c)

z(s) < z(c) - 2,66 < -1,64

Therefore as z(s) < z(c) z(s) is in the rejection zone we reject the null hypothesis

5 0

3 years ago