Answer:
Required time t=5.8s
Explanation:
Given data
Acceleration a=3.08 m/s²
Speed v=29.4 m/s
Required
How much time t is required
Solution
As the train passes through the crossing its motion is described by:
Substitute the given values
So
So time required can be calculated by:
Required time t=5.8s
Answer:
tanong mo kay gugel..wag dito nabobobo ako
Answer: The 6 kg rock sitting on a 3.2 m cliff.
Explanation:
The potential energy of an object of mass M that is at a height H above the ground us:
U = M*H*g
where g is the gravitational acceleration:
g = 9.8m/s^2
Then:
"An 8 kg rock sitting on a 2.2 m cliff"
M = 8kg
H = 2.2m
U = 8kg*2.2m*9.8 m/s^2 = 172.48 J
"a 6 kg rock sitting on a 3.2 m cliff"
M = 6kg
H = 3.2m
U = 6kg*3.2m*9.8m/s^2 = 188.16 J
You can see that the 6kg rock on a 3.2m cliff has a larger potential energy.
Complete Question
The complete question is is shown on the first uploaded
Answer:
The elastic potential energy at point B is
The kinetic energy at point D is
Explanation:
Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is
So at point B
KE at point B is 50J
So
Now at point D
at point D is 25J
So
Answer:1.513 rps
Explanation:
Given
Diameter of cylindrical space
When the station rotates it creates centripetal acceleration which is given by
Now it must create the effect of gravity so
and
Thus