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andre [41]
3 years ago
13

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station 780 m diameter rotatin

g about its central axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity?
Physics
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:1.513 rps

Explanation:

Given

Diameter of cylindrical space d=780\ m

When the station rotates it creates centripetal acceleration which is given by

a_c=\omega ^2r

Now it must create the effect of gravity so

g=\omega ^2r

\omega =\sqrt{\frac{g}{r}}

\omega =0.158\ rad/s

and \omega =\frac{2\pi N}{60}

Thus N=\frac{4.755}{3.142}

N=1.513\ rps

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Irina-Kira [14]

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Explanation:

Assumption:

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final velocity of the ball, v = 0

time of flight is given by;

v = u -gt

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(2)

Given;

initial velocity of the golf, u = 0

final velocity of the golf, v = 34 m/s

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initial velocity of the rocket, u = 27 m/s

time of motion, t = 4.8s

final velocity, v = ?

v = u + gt

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v = 27 - 47.04

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final velocity of the lizard at maximum height, v = 0

the height rose by the lizard is given by;

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