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andre [41]
3 years ago
13

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station 780 m diameter rotatin

g about its central axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity?
Physics
1 answer:
ser-zykov [4K]3 years ago
5 0

Answer:1.513 rps

Explanation:

Given

Diameter of cylindrical space d=780\ m

When the station rotates it creates centripetal acceleration which is given by

a_c=\omega ^2r

Now it must create the effect of gravity so

g=\omega ^2r

\omega =\sqrt{\frac{g}{r}}

\omega =0.158\ rad/s

and \omega =\frac{2\pi N}{60}

Thus N=\frac{4.755}{3.142}

N=1.513\ rps

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A 0.0450-kg golf ball initially at rest is given a speed of 25.2 m/s when a club strikes. part a part complete if the club and b
Ksenya-84 [330]
We are given information:
m = 0.0450 kg
Δv = 25.2 m/s
Δt = 1.95 ms = 0.00195s

To find force we use formula:
F = m * a

a is acceleration. To find it we use formula:
a = Δv / Δt 
a = 25.2 / 0.00195
a = 12923.1 m/s^2

Now we can find force:
F = 0.0450 * 12923.1
F = 581.5 N 


To check the effect of the ball's weight on this movement we need to calculate it and then compare it to this force.
W = m * g
W = 0.0450 * 9.81
W = 0.44145 N 

We can see that weight is much smaller than the applied force so it's influence in negligible.
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3 years ago
Solve the problem.
gulaghasi [49]
As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
area of a circle =<span>π</span><span>r*r</span>

d=120
<span>r=<span>120/2</span></span><span>r=60</span><span><span>60*60</span>=3600</span><span>3600*π=11309.734</span>
<span>11309.734 square miles</span>
5 0
3 years ago
Please give answer with solution​
UNO [17]
250 m. for a longer explanation or solution look at this article, i’m sorry.
https://www.quora.com/A-projectile-is-thrown-so-it-travels-a-maximum-range-of-1000m-How-high-will-it-rise
3 0
3 years ago
Define output work and input work​
Olenka [21]

Answer: Input work is the work done on a machine as the input force acts through the input distance.Other ways it would be the work done on a body or system, that is, forces that are applied to the body or system. This is in contrast to output work which is a force that is applied by the body or system to something else.Output work is the work done by a machine as the output force acts through the output distance. The machine does to the object to increase the output distance.

Explanation:

6 0
3 years ago
What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
mrs_skeptik [129]

Answer:

x = 2\sqrt 2

Explanation:

Given

Hypotenuse = 4

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

x^2 + x^2 = 4^2 --- i.e. the other legs are equal

So, we have:

2x^2 = 16

Divide both sides by 2

x^2=8

Take square roots of both sides

x = \sqrt 8

Simplify

x = 2\sqrt 2

5 0
2 years ago
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