uniform circular motion. tangential speed constant. direction changes
V - the wind velocity;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Answer: The wind velocity is 21 m/s.
Answer:
is the final velocity of the racket.

Explanation:
Given:
- mass of the racket,

- mass of ball,

- initial speed of racket,

- initial speed of ball,

- final speed of ball,

- time of contact of racket with the ball,

<u>By the law of conservation of momentum:</u>

where:
final velocity of the racket

is the final velocity of the racket.
<u>By the Newton's second law of motion:</u>
............................(1)
where:
dp = change in momentum
dt = change in time
Change in momentum of ball:



Now, using eq.(1):


A parasitic relationship is one in which one organism, the parasite, lives off of another organism, the host, harming it and possibly causing death. The parasite lives on or in the body of the host. A few examples of parasites are tapeworms, fleas, andbarnacles.
Answer:
Explanation:
Give that,
Mass of object
Ma = 40kg
Mb = 35kg
Velocity of mass A Va = 50m/s
Velocity of mass B Vb = 30m/s
Since after collision the two bodies stick together(inelastic collision), then, they will have a common velocity
Let assume common velocity V
So using conservation of linear momentum
Momentum before collision is equal to momentum after collision
P(before) = P(after)
Note P = mV and momentum is a vector quantity
So we assume, that the small mass is moving in the negative direction
P(before) = P(after)
Ma•Va —Mb•Vb = (Ma+Mb)V
40×50—35×30 = (40+35)V
950 = 75V
Then, V = 950/75
V = 12.67 m/s
The common velocity is 12.67 m/s