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Minchanka [31]
3 years ago
9

HELP ME PLEASE I LOVE U

Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

\huge \purple{\tt{Answer:}}

Mr. Chase , because the answer is 324

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MEDAAAL :D
Sonja [21]
<span>The answer is 2431.01. At the end of the first year, 5 percent of 2000 is taken and added on to the 2000 you started with. At the end of the second, another 5 percent of that higher number is taken and added on, and so on and so forth until you end up receiving 2431.01 in total after 4 years.</span>
8 0
3 years ago
Step 1: –10 + 8x &lt; 6x – 4
vesna_86 [32]

The final step in solving the inequality is to divide through by -2 and flip the sign

<h3>Solving Inequalities </h3>

From the question, we are to determine the final step in solving the inequality

The given inequality and the steps for solving are

Step 1: –10 + 8x < 6x – 4

Step 2: –10 < –2x – 4

Step 3: –6 < –2x

The final step will be to divide both sides of the inequalities by -2 and then flip the sign

That is,

–6 < –2x

Divide both sides by -2 and flip the sign

3 > x

OR

x < 3

Hence, the final step in solving the inequality is to divide through by -2 and flip the sign

Learn more on Solving inequalities here: brainly.com/question/246993

#SPJ1

4 0
2 years ago
First terms of sequence 4n-3
olga_2 [115]

Answer:

а1 4*1-3=4-3=1

а2 4*2-3=8-3=5

а3 4*3 -3=12-3=9

а4 4*4 -3=16-3=13

а5 4*5 -3=20-3=17

5 0
3 years ago
If the angle of angle one is 24 then the measure of angle 4 is
bearhunter [10]

i dont know this one sorry

3 0
4 years ago
Let C = {n ∈ Z | n = 6r – 5 for some integer r} and D = {m ∈ Z | m = 3s + 1 for some integer s}.
noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

Proof : Let n ∈ C

Then there exists an integer r such that:

n = 6r - 5

Since -5 = -6 + 1

=> n = 6r - 6 + 1

Using distributive property,

=> n = 3(2r - 2) +1

Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then

Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

7 0
2 years ago
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