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just olya [345]
3 years ago
12

What is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second?

Physics
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

500 J

Explanation:

Kinetic Energy = (mass x velocity x velocity) ÷ 2

We know that mass = 10 kg and velocity = 10 m/s.

KE = (m × v × v) ÷ 2

KE = (10 kg × 10 m/s × 10 m/s) ÷ 2

KE = 500 J

The kinetic energy of the object is 500 J (joules). Hope this helps, thank you !!

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Answer:

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3 years ago
1)the car's engine power is 44000W. Explain this number in a physical sense
Ratling [72]

Answer:

1) It expresses the rate (top speed) at which it can move with time.

2) P = 20 W

3) h = 18 km

Explanation:

1) Power is the rate of transfer of energy.

⇒ Power = \frac{Energy(or workdone)}{Time}

i.e P = \frac{E}{t}

Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.

2) m = 400g = 0.4 kg

    t = 20 s

h = 100m

g = 10 m/s^{2}

P = \frac{mgh}{t}

  = \frac{0.4*10*100}{20}

  = \frac{400}{20}

P = 20 W

3) u = 600 m/s

   g = 10 m/s^{2}

From the third equation of free fall,

V^{2} = U^{2} - 2gh

V is the final velocity, U is the initial velocity, h is the height.

0 = (600)^{2} - 2 x 10 x h

0 = 360000 - 20h

20h = 360000

h = \frac{360000}{20}

  = 18000

h = 18 km

The maximum height of the bullet would be 18 km.

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3 years ago
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Let’s say you have a spring. You press on the spring with your finger. The spring goes down. This is the action force. Then, the spring goes back up after you take your finger off of it. This is known as the reaction force.
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luda_lava [24]
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3 years ago
A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t
aleksandr82 [10.1K]

Answer:

Acceleration: 9800 ft/s^2

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

t = 0.5 s (time taken)

Therefore, the acceleration is

a=\frac{5000-100}{0.5}=9800 ft/s^2

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