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3 years ago

from an origin you walk 3 meters east 7 meters west and then 6meters east . where are you now relative to the origin?

1 answer:

german3 years ago

3 0

You take 3 steps east, turn around & take another 7 steps west (4 steps always from origin) you turn around again and take 6 more steps east - 2 steps always from origin

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Sam is pulling a box up to the second story of his apartment via a string. The box weighs 53.3 kg and starts from rest on the gr

castortr0y [4]

Answer:

W = 1222.4 J = 1.22 KJ

Explanation:

The work done on an object is the product of the force applied on it and the displacement it covers as a result of this force. It must be noted that the component of displacement in the direction of force should only be used. Hence, the work can be calculated as:

W = F d Cosθ

where,

W = Work Done = ?

F = Force Applied = 64 N

d = Distance Covered by Box = 19.1 m

θ = Angle between force and displacement = 0°

Therefore,

W = (64 N)(19.1 m)Cos 0°

7 0

3 years ago

Is it true or false that air pollution only occurs as a result of human activity

gregori [183]

Hi alexander it is very true air pollution is only caused by human activity

8 0

3 years ago

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only a relatively small part of the electromagnetic spectrum is visible. what determines which bands of the electromagnetic spec

swat32

Answer:

hsnzbssj

Explanation:

<h2>skibbbbbbbbbbbbibi</h2>

3 0

3 years ago

Final velocity will be greater than initial velocity of an object is

Natali [406]

Answer:

accelerating

Explanation:

If we consider(v > u) Acceleration:

final velocity(v)= 14m/s

initial velocity(u)=10m/s

time taken(t)= 2 seconds

a= $\frac{(v-u)}{t} =\frac{(14-10)}{2}$ =2m/s²

If we consider (v<u) Deceleration:

final velocity(v)= 3m/s

initial velocity(u)=9m/s

time taken(t)=2 seconds

a= $\frac{(v-u)}{t}=\frac{(3-9)}{2}$ = -3m/s²

4 0

3 years ago

A Boeing 777 aircraft has a mass of 300,000 kg. At a certain instant during its landing, its speed is 27.0 m/s. If the braking f

GarryVolchara [31]

Answer:

Speed of the airplane 10.0 s later = 12.2 m/s

Explanation:

Mass of Boeing 777 aircraft = 300,000 kg

Braking force = 445,000 N

Deceleration

$a=\frac{445000}{300000}=1.48m/s^2$

Initial velocity, u = 27 m/s

Time , t = 10 s

We have equation of motion, v =u +at

v = 27 + (-1.48) x 10 = 27 - 14.8 = 12.2 m/s

Speed of the airplane 10.0 s later = 12.2 m/s

6 0

3 years ago