I am not all understood but for the school to earn money you can:
make
--a raffle
--lotto
-- yard sale
-- class photo
-- origami for sale or something
-- buffet or food sale (example all Friday ice cream sale, 2 livre ice cream)
Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.
81. There is 1 carbon, 2 chlorine and fluorine atoms in Freon 12. To draw them it forms a cross with C in the middle and Cl and F both on the opposite side.
Cl
l
F - C- F
l
Cl
82. Freon-12 and Freon-14 are called halocarbons or just halides.
Explanation:
Equation of reaction:
CO + 2H₂ ⇒ CH₃OH + energy
a. An increase in pressure:
A change in pressure affects only equilibrium involving a gas or gases. Le Chatelier's principle can be used to predict the direction of displacement.
An increase in pressure on an equilibrium system will shift the position of equilibrium to the side having smaller volume and vice-versa
CO + 2H₂ ⇒ CH₃OH + energy
3 moles 1 moles
An increase in pressure will favor the forward reaction to be favored.
b. Addition of H₂:
An in concentration of a specie favors the direction that uses up that specie and lowers its concentration.
Addition of hydrogen gas increases the concentration of amount of substances reacting.
To annul the effect of the reactant, more the product is given. The equilibrium shifts in the forward direction.
learn more:
equilibrium brainly.com/question/5877801
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We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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