Which describes any compound that has at least one element from group 17?

How many formula units are in 239.2g of <br> Br2<br> MgCl2<br> H2O<br> Fe

Oksana_A [137]

The formula units in the substances are as follows:

Br2 = 8.99 × 10^23 formula units
MgCl2 = 1.51 × 10^24 formula units
H2O = 2.57 × 10^24 formula units
Fe = 2.57 × 10^24 formula units

<h3>How many moles are in 239.2 g of the given substances?</h3>

The moles of the substances are determined from their molar mass.

Molar mass of the substances is given as follows:

Br2 = 160 g/mol
MgCl2 = 95 g/mol
H2O = 18 g/mol
Fe = 56 g/mol

Formula units = mass/molar mass × 6.02 × 10^23

The formula units in the substances are as follows:

Br2 = 239.2/160 × 6.02 × 10^23 = 8.99 × 10^23 formula units
MgCl2 = 239.2/95 × 6.02 × 10^23 = 1.51 × 10^24 formula units
H2O = 239.2/18 × 6.02 × 10^23 = 2.57 × 10^24 formula units
Fe = 239.2/56 × 6.02 × 10^23 = 2.57 × 10^24 formula units

In conclusion, the number of formula units is derived from the moles and Avogadro number.

Learn more about formula units at: brainly.com/question/24529075

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6 0

2 years ago

Write a definition for each word and use each word in a sentence.<br> crystallization and organic

Artemon [7]

Answer:

Crystallization is the solidification of atoms or molecules into a highly structured form called a crystal.

Explanation:

Organic chemistry is the scientific study of the structure, properties, composition, reactions, and synthesis of organic compounds

3 0

3 years ago

In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch

LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of copper (II) chloride.

$M_2\text{ and }V_2$ are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

$M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?$

Putting values in above equation, we get:

$0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL$

Hence, the volume of stock solution needed are, 12.5 mL

8 0

3 years ago

How many atoms of cobalt are in 4 moles of cobalt?

Anna [14]

<h3>Answer:</h3>

2 × 10²⁴ atoms Co

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

4 mol Co (Cobalt)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 4 \ mol \ Co(\frac{6.022 \cdot 10^{23} \ atoms \ Co}{1 \ mol \ Co})$
Multiply/Divide: $\displaystyle 2.4088 \cdot 10^{24} \ atoms \ Co$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

2.4088 × 10²⁴ atoms Co ≈ 2 × 10²⁴ atoms Co

4 0

2 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

sveta [45]

Explanation:

The given data is as follows.

$E^{o}$ = 0.483, $[Co^{3+}]$ = 0.173 M,

$[Co^{2+}]$ = 0.433 M, $[Cl^{-}]$ = 0.306 M,

$P_{Cl_{2}}$ = 9.0 atm

According to the ideal gas equation, PV = nRT

or, P = $\frac{n}{V}RT$

Also, we know that

Density = $\frac{mass}{volume}$

So, P = MRT

and, M = $\frac{P}{RT}$

= $\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}$

= $\frac{9.0}{24.436}$

= 0.368 mol/L

Now, we will calculate the cell potential as follows.

E = $E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}$

= $0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}$

= $0.483 - 0.02955 log \frac{0.0689}{0.0162}$

= $0.483 - 0.02955 \times 0.628$

= 0.483 - 0.0185

= 0.4645 V

Thus, we can conclude that the cell potential of given cell at $25^{o}C$ is 0.4645 V.

4 0

3 years ago