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MrMuchimi
2 years ago
12

Does anyone know how to do this?

Chemistry
1 answer:
mr Goodwill [35]2 years ago
4 0

Answer:

this look hard

Explanation:

hmm

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PLEASE HELP MY TEACHER IS GOING TO SEE ME AFTER CLASS
Crazy boy [7]

Answer:

The Nucelous helps prevent bad cells in

Explanation:

6 0
2 years ago
If 0.60 L of a solution contains 6.6 g of NaBr, what is its molar concentration?
-BARSIC- [3]

Answer:

Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

Br = 79.904

molar mass of NaBr = 102.893769

6.6g ÷ 102.893769 = 0.064143826 moles of NaBr

0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %

7 0
3 years ago
Pcl3+H2O=H3PO3+Hcl=?​
beks73 [17]

Answer:

PCl3 + 3H2O → HPO(OH)2 + 3HCl. Phosphorus(III) chloride react with water to produce phosphorous acid and hydrogen chloride.

Explanation:

7 0
2 years ago
Read 2 more answers
Enter your answer in the provided box. When mixed, solutions of barium chloride, BaCl2, and potassium chromate, K2CrO4, form a y
ira [324]

Answer:

35.42g

Explanation:

Step 1:

The balanced equation for the reaction

BaCl2(aq) + K2CrO4(aq) → BaCrO4(s) + 2KCl(aq)

Step 2:

Determination of the limiting reactant.

It is important to determine which of the reactant is limiting the reaction as the limiting reactant is used to determine the maximum yield of the reaction. The limiting reactant can be determined as follow:

From the balanced equation above,

1 mole of BaCl2 reacted with 1 mole of K2CrO4.

Therefore, 0.7 mole of BaCl2 will also react with 0.7 mol of K2CrO4.

From the above illustration, we can see that it requires a higher amount of K2CrO4 to react with 0.7 mol of BaCl2. This simply means that K2CrO4 is the limiting reactant.

Step 3:

Determination of the number of mole of BaCrO4 produced from the reaction.

The limiting reactant is used in this case.

From the balanced equation above,

1 mole of K2CrO4 produced 1 mole of BaCrO4.

Therefore, 0.14 mole of K2CrO4 will also produce 0.14 mole of BaCrO4.

Step 4:

Converting 0.14 mole of BaCrO4 to grams.

This is illustrated below:

Molar Mass of BaCrO4 = 137 + 52 + (16x4) = 137 + 52 + 64 = 253g/mol

Number of mole BaCrO4 = 0.14 mole

Mass of BaCrO4 =?

Mass = number of mole x molar Mass

Mass of BaCrO4 = 0.14 x 253

Mass of BaCrO4 = 35.42g

Therefore, 35.42g of BaCrO4 is produced from the reaction.

4 0
3 years ago
Is the equation balanced or unbalanced? Explain. AI + O2 --> AI2O3
anastassius [24]

Answer:

unbalanced..........

6 0
2 years ago
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