Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 *
cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π *
*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π *
*l
= 
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
=
*
= 
Due to the law of conservation of mass, _g K + 16g O=94g KO.
So, 94-16=78
78 is your answer
The tiny positive<span> core of </span>an atom<span>; contains protons and neutrons. the paths in which electrons circle the nucleus according to the Bohr model. building blocks of matter represented by a symbol. </span>
About 2 gallons. (I got 1.92592592593)