In question 13 answer B is the correct one since a catalyst is a chemical that can be added to a reaction to increase the reaction rate without being consumed in the process. In this way, a catalyst accelerates a reaction by decreasing the energy barrier necessary for the reaction to occur or by changing the reaction mechanism. The most common types of catalysts are enzymes, acid base catalysts and heterogeneous catalysts, mostly composed of solids in which the reactants adhere.
In the reaction you have in the question, they use an acid catalyst, H3O+. This catalyst changes the reaction mechanism of 2-butene in 1-butene without being consumed, since it appears at the beginning and at the end of the transformation of 2 butene into 1-butene. The reaction mechanism would be the following
In question 14 the correct answer is option B since the law of velocity of a reaction will be governed by the slow step of the mechanism through which it occurs. In the slow step the chemical species have a harder time transforming because they need more energy to do it, then they will do it in a slower way and the reaction will take longer to occur. Therefore, the slow step is the one that will determine the total speed of the reaction and the speed law must be in terms of that process. The speed of the other two steps is so fast that it is negligible.
I1f calcium lost 2 electrons, it would have the same number of electrons as Argon.
Answer:
670.68°C
Explanation:
Given that:
volume of water = 50 ml but 1 g = 1 ml. Therefore the mass of water (m) = 50 ml × 1 g / ml = 50 g
specific heat (C) = 4.184 J/g˚C
Initial temperature = 20°C, final temperature = 22°C. Therefore the temperature change ΔT = final temperature - initial temperature = 22 - 20 = 2°C
The quantity of heat (Q) used to raise the temperature of a body is given by the equation:
Q = mCΔT
Substituting values:
Q = 50 g × 4.184 J/g˚C × 2°C = 418.4 J
Since the mass of lead = 5 g and specific heat = 0.129 J/g˚C. The heat used to raise the temperature of water is the same heat used to raise the temperature of lead.
-Q = mCΔT
-418.4 J = 5 g × 0.129 J/g˚C × ΔT
ΔT = -418.4 J / ( 5 g × 0.129 J/g˚C) = -648 .68°C
temperature change ΔT = final temperature - initial temperature
- 648 .68°C = 22°C - Initial Temperature
Initial Temperature = 22 + 648.68 = 670.68°C
Answer:
uhhh im not a boy ima just answer this for points
Explanation:
:))))
True, i'm pretty sure it does
