Answer: The possible structure for this compound is 2,4-dimethyl-3-pentanone
Explanation:
It should be noted that, If the 1H NMR spectrum of a compound with formula C7H14O gives a doublet at 9.2 ppm. The possible structure for this compound is 2,4-dimethyl-3-pentanone
Answer:
a)mCH3COONa=?, Vsln=50mL(0.05L); [sln]=0.1M∴M≡(mol/L)
b)VslnNaOH=?; [slnNaOH]=1M; Vsln2=10mlcf; [sln2]=0.1M
Explanation:
a) PMCH3COONa=82.03g/mol
⇒ 0.05L*0,1mol/L*82.03g/mol = 0.4102g CH3COONa
R/ mCH3COONa = 0.4102g
b) V1*M1 =V2*M2......dilution form.
⇒V1*(1M) = (10mlcf)*(0.1M)
⇒V1 = ((10mlcf)*(0.1M))/(1M)
⇒V1 = 1mlcf
R/ Vsln NaOH = 1mlcf
-1 charge = the atom has gained one electron
9+1=10
You could find some concreat and draw some yards with chalk and write down the results
