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n200080 [17]
3 years ago
12

Please help what are the number atoms for each?!

Chemistry
1 answer:
krok68 [10]3 years ago
6 0

Answer:

AI 2 ,CR 2, O 7

Explanation:

Tbh ion even know bro like imma need more info to answer that one cheif

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An old antacid commercial claimed that each tablet of their product could neutralize 47 times its mass in stomach acid. The acti
butalik [34]

Answer : The number of moles of HCl neutralize is, 0.00824 moles.

Explanation :

The given balanced chemical reaction is:

NaAl(OH)_2CO_3+4HCl\rightarrow NaCl+AlCl_3+3H_2O+CO_2

First we have to calculate the moles of NaAl(OH)_2CO_3

\text{Moles of }NaAl(OH)_2CO_3=\frac{\text{Mass of }NaAl(OH)_2CO_3}{\text{Molar mass of }NaAl(OH)_2CO_3}

Molar mass of NaAl(OH)_2CO_3 = 144 g/mol

\text{Moles of }NaAl(OH)_2CO_3=\frac{0.296g}{144g/mol}=0.00206mol

Now we have to calculate the moles of HCl.

From the balanced chemical reaction we conclude that,

As, 1 mole of NaAl(OH)_2CO_3 react with 4 moles of HCl

So, 0.00206 mole of NaAl(OH)_2CO_3 react with 0.00206\times 4=0.00824 moles of HCl

Thus, the number of moles of HCl neutralize is, 0.00824 moles.

8 0
3 years ago
You weigh two different objects on the same scale in the same location on Earth. The weights are different. What must be differe
timofeeve [1]
They can be differnt shape or one must weight more then the other one
3 0
3 years ago
Read 2 more answers
A piece of aluminum has a volume of 12 cm3and a mass of 32 g. What is its density? Do not forget the units.
Contact [7]

Answer:

<h3>The answer is 2.67 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of metal = 32 g

volume = 12 cm³

The density is

density =  \frac{32}{12}  =  \frac{8}{3}  \\  = 2.6666666...

We have the final answer as

<h3>2.67 g/cm³</h3>

Hope this helps you

3 0
3 years ago
HELPPP
maxonik [38]

1 endothermic 2 yes and exothermic 3 endothermic

3 0
3 years ago
Hexane is a common laboratory solvent and a component of petrol. Its combustion reaction is as follows: 2 C6H14 (9) + 19 02(9) +
Flauer [41]

Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is, 1.01\times 10^3

Explanation :

The given balanced reaction is,

2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(l)

Given:

Moles of hexane = 0.121 mol

\Delta H = -8326 kJ/mol

The negative sign indicate that the reaction exothermic or amount of heat released.

As, 1 mole of hexane released heat = 8326 kJ

So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈ 1.01\times 10^3kJ

Therefore, the heat released by the combustion of 1.121 mol of hexane is 1.01\times 10^3kJ.

4 0
4 years ago
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