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iren2701 [21]
4 years ago
7

What is the oxidation number of chromium in the ionic compound ammonium dichromate (nh4)2cr2o7?

Chemistry
1 answer:
lesya692 [45]4 years ago
4 0
The oxidation number of an element is the number of electrons that are gained or lost by the element to form a chemical bond. 
the net oxidation number of the ion is its charge.
compound (NH₄)₂Cr₂O₇ is made of cation - NH₄⁺ and anion - Cr₂O₇²⁻
oxidation number of ion - -2
(oxidation number of Cr x 2 Cr atoms) +(oxidation number of O x 7 O atoms )= -2
oxidation number of Cr = y
oxidation number of O = -2
(y x 2) + (-2 x 7) = -2
2y - 14 = -2
2y = 12
y  = + 6
therefore oxidation number of Cr is +6 
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