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vladimir2022 [97]
2 years ago
13

Mai skated x miles, and Clare skated ⅗ farther than that. Write an expression for the distance Clare skated.

Mathematics
1 answer:
Eddi Din [679]2 years ago
4 0

Answer:

Its either 8x/5 or 5x/8

im not sure sorry.

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7. Graph 3x + 4y = 8​
Romashka-Z-Leto [24]

Answer:

y= -3/4x+2

Step-by-step explanation:

3x+4y=8

-3x       -3x

----------------

4y=-3x+8

Divided by 4 on each sides

y= -3/4x+2

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3 years ago
Write standard form twenty-five thousand, four hundred eight
hoa [83]
In standard form it is 25,408
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Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).
alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))=C\cdot Sum of diagonal elements of A

C(Tr(B))=C\cdot Sum of diagonal elements of B

C(A+B)=C\cdot (A+B)

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]

B=\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B=\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]

A+B=\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]

C(A+B)=\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

5 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 7.8 c
Kobotan [32]

Answer:

its b ive had this question before

6 0
2 years ago
An independent-measures study with n = 6 in each sample produces a sample mean difference of 4 points and a pooled variance of 1
attashe74 [19]
6=60 4=40. 12=120 their is your answer
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3 years ago
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