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3 years ago

6.) Convert the following linear equation into slope-intercept form. 4x + 3y = 9

Mathematics

2 answers:

kkurt [141]3 years ago

6 0

4x+3y-9=0

yeetis to the feetis

viktelen [127]3 years ago

5 0

Answer:

$y=\frac{-4}{3} +9$

Step-by-step explanation:

Slope-intercept form is y-mx+b. To find slope-intercept form solve for y.

First, subtract 4x from both sides,

3y=-4x+9

Then, divide both sides by 3,

y=-4/3x+3

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A spinning giant star of initial radius R1 and angular speed ω1 suddenly collapses radially inward reaching a new radius R2 = 0.

tiny-mole [99]

Answer:

K1/K2=4

Step-by-step explanation:

The kinetic energy of a rotating sphere is given by:

$K=\frac{I*\omega^{2} }{2}$

The moment of inertia of a solid sphere is given by

$I=\frac{2MR^{2} }{5}$

The initial kinetic energy is therefore

$K_1=\frac{2MR^{2}*\omega^{2} }{10}$

$K_1=\frac{MR_1^{2}*\omega^{2} }{5}$

The final kinetic energy is given by

$K_2=\frac{MR_2^{2}*\omega^{2} }{5}$

Therefore the relation K1/K2 if R2 = 0.5R1

$\frac{K_1}{K_2} =\frac{5M(R_1)^{2}*\omega^{2} }{5*M(0.5R_1)^{2} \omega^{2}}$

The text says nothing about the final angular velocity just the collapse of the collapse of the radius

$\frac{K_1}{K_2} =\frac{1 }{(0.5)^{2} }=4$

3 0

3 years ago

Are polynomials determined to be a trinomial, binomial, etc. based on the number of operations or the terms?

Mekhanik [1.2K]

Polynomials are determined to be a trinomial, binomial, etc by the amount of terms they have
For example
7x+3 is a binomial

5 0

3 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$