David gave 1/5 of his oranges to his brother. his brother got 15 oranges. he gave his friend donny 1/3 of the remainder.

What is equivalent expression 9y+y

andrew11 [14]

Answer:

10y

Step-by-step explanation:

9y+y=

10y

4 0

3 years ago

4.1g + 8= 1.1g + 14 what is g?

Monica [59]

Answer:

Step-by-step explanation:

5.2g +8=0

5.2g=-8

g=-1.54

8 0

3 years ago

Read 2 more answers

Write 125 as a product of primes. Use index notation when giving your answer.

Mnenie [13.5K]

Answer:

5^3

Step-by-step explanation:

125= 5*25

25=5*5

5 is a prime number and there are 3 of them so the answer in index notation will be 5^3

3 0

2 years ago

mestny [16]

Answer:

12... If there is an even ratio between the two, then there is an even amount, so you divide 24 by 2 and you have 12 chocolate and 12 vanilla cupcakes in the Grande box.

Step-by-step explanation:

It izz wat it izzzz!!!

:)

5 0

3 years ago

Read 2 more answers

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let x be the width and y the length of the rectangular field.

Let C the total cost of the rectangular field.

The side made of heavy duty material of length of x costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are x, y, y. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

2 years ago