Answer: Choice A) cone
One way to picture this is to think of a propeller. As the propeller spins, it carves out a 3D space even though the blade is "2D" in a sense.
If we spin everything around segment BC, we get a 3D cone forming. The base of the cone is vertical and it has a radius of AC. The height of the cone is segment BC. It might help to rotate the paper 90 degrees clockwise so that BC is vertical.
Answer:
half hour
Step-by-step explanation:
Do 1 fourth times two
Answer:
9:12 and 12:16
Step-by-step explanation:
3/4 = 0.75
9/12 = 0.75
12/16 = 0.75
answer: could be both (B)and(C)
Step-by-step explanation:
Answer:
![x= 7, y=4\sqrt{2}](https://tex.z-dn.net/?f=x%3D%207%2C%20y%3D4%5Csqrt%7B2%7D)
<em>Correct option B.</em>
Step-by-step explanation:
The diagram shows a trapezoid with a base angle of 45° and the other base angle of 90°.
We have completed the diagram to draw a perpendicular line over the base of height h=4. A triangle is formed with an angle of 45°.
Recall a right triangle with angles of 45° is isosceles, thus the base and the height are h=4. Please check the diagram below.
For that triangle, we apply Pythagora's Theorem:
![y^2=4^2+4^2=2*4^2](https://tex.z-dn.net/?f=y%5E2%3D4%5E2%2B4%5E2%3D2%2A4%5E2)
Thus:
![y=\sqrt{2*4^4}=4\sqrt{2}](https://tex.z-dn.net/?f=y%3D%5Csqrt%7B2%2A4%5E4%7D%3D4%5Csqrt%7B2%7D)
![y=4\sqrt{2}](https://tex.z-dn.net/?f=y%3D4%5Csqrt%7B2%7D)
The base of the trapezoid x is h + 3 = 7
Thus:
![\mathbf{x= 7, y=4\sqrt{2}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3D%207%2C%20y%3D4%5Csqrt%7B2%7D%7D)
Correct option B.