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ziro4ka [17]
3 years ago
14

Help me pleaaaassssseee

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0
Add the amount of choices, and divide by the number of customers surveyed.

40 + 32 + 8 + 20 = 100

40 customers were surveyed

100/40 = 2.5

The average number should be D) 2.5

hope this helps
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A number is chosen at random from 1 to 50. Find the probability of selecting either a multiple of 4 or a multiple of 5.
anygoal [31]
A multiple of 4 is a 12/50 chance and a multiple of 5 is a 10/50 chance or simplified 1/5 chance
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A seal went 15 feet below sea level to catch a fish. A sea lion dove 6 feet less than two times as deep as the seal to catch a l
Ne4ueva [31]
15-6x2=X im not sure if thats right but its what i got
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Please round to the nearest tenth if possible.
Butoxors [25]
\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
\cfrac{6000~\underline{lbs}}{\underline{day}}\cdot \cfrac{ton}{2000~\underline{lbs}}\cdot \cfrac{7~\underline{day}}{week}\implies \cfrac{6000\cdot 7~ton}{2000~week}\implies 21.00\frac{ton}{week}

\bf -------------------------------\\\\
\cfrac{2~\underline{lbs}}{\underline{week}}\cdot \cfrac{16~oz}{\underline{lbs}}\cdot \cfrac{\underline{week}}{7~day}\implies \cfrac{2\cdot 16~oz}{7~day}\implies \cfrac{32~oz}{7~day}\approx 4.57\frac{oz}{day}
8 0
4 years ago
Evaluate log (0.3).<br> Round your answer to the nearest thousandth.
djverab [1.8K]

Answer:

-0.523

Step-by-step explanation:

log(a/b)=loga-logb

log (0.3) can be written as log (3/10).

=log(3/10)

=log3-log10

=0.477-1 (log3=0.477 and log10=1)

= -0.523

5 0
3 years ago
Estimate the minimum number of subintervals to approximate the value of Integral from negative 3 to 3 (2 x squared plus 9 )dx wi
vichka [17]

Answer:

The value of n for (a) n=425. (b) n=0.

Step-by-step explanation:

Given integration is,

\int_{-3}^{3}f(x)=\int_{-3}^{3}(2x^2+9)dx

(a) For Trapezoidal Rule : Composite error is,

E_T=-\frac{(b-a)^3}{12n^2}f''(x_m)

Where, f''(x_m)=greatest value of |f''(x)|= |4|=4, a=-3, b=3. Therefore to find the minimum number of subinterval,

|E_T|\leq | \frac{(b-a)^3}{12n^2}f''(x)||

\leq \frac{4(-3-3)^3}{12n^2}

=\frac{72}{n^2}

According to the question, we must choose n such that,

\frac{72}{n^2}

\implies n>424.2640686

So we can take n=425.

(b) For Simpson 1/3 rule : Composite error is,

E_S=-\frac{(b-a)^5}{180n^4}f^{(iv)}(x_m)

where, f^{(x_m)}=\textit{greatest value of} |f^{(iv)}(x)|

In this problem f^{(iv)}(x)=0, so that,

|E_S|\leq 0

that is there exist no error. So n=0.

6 0
3 years ago
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