Answer:
0.003060 cm³
Explanation:
Mass of water = m = 326.75 gram
Density of water = ρ = 1.00 g/mL = 1 g/cm³
density = mass / volume
⇒volume = density / mass
⇒volume = 1 / 326.75
⇒Volume = 0.0030604 cm³
∴ Volume held by beaker = 0.0030604 cm³
Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.
Answer:
θ = 12.60°
Explanation:
In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:
(1)
θ: angle below he horizontal
vy: y component of the velocity just after the puck hits the ground
vx: x component of the velocity
The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:

vo: initial velocity = 28.0 m/s
The y component is calculated with the following equation:
(2)
voy: vertical component of the initial velocity = 0m/s
g: gravitational acceleration = 9.8 m/s^2
y: height
You solve the equation (2) for vy and replace the values of the parameters:

Finally, you use the equation (1) to find the angle:

The angle below the horizontal is 12.60°
Answer:
50°C = 122 Fahrenheit
Explanation:
Here, we need to convert 50°C to F i.e. Fahrenheit. The conversion formula from degree Celsius to Fahrenheit is as follows :

Where, 


So, 50 degree Celsius is equal to 122 degree Fahrenheit. Hence, this is the required solution.