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natita [175]
3 years ago
13

Is there any way u can help me

Physics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

get help with your work

try understand your work

ask your teacher for assistance or class

or maybe cheat but understand the work first if you wanna

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What kind of weather system encourages a thunderstorm to develop
valentina_108 [34]
Low pressure systems
6 0
4 years ago
When completely filled with water, the beaker and its contents have a total mass of 326.75 g. What volume does the beaker hold?
miv72 [106K]

Answer:

0.003060 cm³

Explanation:

Mass of water = m = 326.75 gram

Density of water = ρ = 1.00 g/mL = 1 g/cm³

density = mass / volume

⇒volume = density / mass

⇒volume = 1 / 326.75

⇒Volume = 0.0030604 cm³

∴ Volume held by beaker = 0.0030604 cm³

Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.

6 0
3 years ago
A hockey puck slides off the edge of a horizontal platform with an initial velocity of 28.0 m/shorizontally in a city where the
kozerog [31]

Answer:

θ = 12.60°

Explanation:

In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:

\theta=tan^{-1}(\frac{v_y}{v_x})       (1)

θ: angle below he horizontal

vy: y component of the velocity just after the puck hits the ground

vx: x component of the velocity

The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:

v_x=v_o

vo: initial velocity = 28.0 m/s

The y component is calculated with the following equation:

v_y^2=v_{oy}^2+2gy         (2)

voy: vertical component of the initial velocity = 0m/s

g: gravitational acceleration = 9.8 m/s^2

y: height

You solve the equation (2) for vy and replace the values of the parameters:

v_y=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(2.00m)}=6.26\frac{m}{s}

Finally, you use the equation (1) to find the angle:

\theta=tan^{-1}(\frac{6.26m/s}{28.0m/s})=12.60\°

The angle below the horizontal is 12.60°

7 0
3 years ago
Determine the accelerations that result when a 45 N net force is applied to 3kg object
svp [43]

Answer:

acceleration is 18

Explanation:

45N/3kg=18

4 0
3 years ago
Read 2 more answers
50°C is equivalent to a 82 F b- 90"F c 122"F
andre [41]

Answer:

50°C = 122 Fahrenheit

Explanation:

Here, we need to convert 50°C to F i.e. Fahrenheit. The conversion formula from degree Celsius to Fahrenheit is as follows :

^{\circ}F=(^{\circ}C\times \dfrac{9}{5})+32

Where, ^{\circ}C=50^{\circ}C

^{\circ}F=(50\times \dfrac{9}{5})+32

^{\circ}F=122^{\circ} F

So, 50 degree Celsius is equal to 122 degree Fahrenheit. Hence, this is the required solution.

6 0
3 years ago
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