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3 years ago

An automobile engine has an efficiency of 22.0% and produces 2510 J of work. How much heat is rejected by the engine

Physics

1 answer:

katrin [286]3 years ago

5 0

Answer:

If efficiency is .22 then W = .22 * Q where Q is the heat input

Heat Input Q = 2510 / .22 = 11,400 J

Heat rejected = 11.400 - 2510 = 8900 J of heat wasted

Also, 8900 J / (4.19 J / cal) = 2120 cal

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Answer:

I= $\frac{4}{3}ML^2+2MR^2+2MRL$

Explanation:

We are given that

Mass of rod=M

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Radius of hoop=R

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Moment of inertia of the pendulum about the pivot left end,I= $\frac{1}{12}ML^2+M(\frac{L}{2})^2+MR^2+M(L+R)^2$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{1}{12}ML^2+\frac{1}{4}ML^2+MR^2+MR^2+ML^2+2MRL$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{1+3+12}{12}ML^2+2MR^2+2MLR$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{16}{12}ML^2+2MR^2+2MRL$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{4}{3}ML^2+2MR^2+2MRL$

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