Answer:
The answer is given below
Explanation:
Things provided in the statement:
Pressure <em>P1</em> = 120 kPa and <em>P2</em> = 5.6 MP or 5600 kPa
Power, <em>W</em> = 7 kW
Elevation difference = ∆z = 10 m
Mass of flow = m˙
So potential energy changes may be significant
Specific volume of water V= 0.001 m³/kg
Now putting the values in the formula
Power, <em>W </em>= m˙ x V (<em>P1 - P2</em>) + m˙ x g x ∆z
7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)
7 = m˙ x 5.48 + m˙ x 0.098
7 = m ˙x 5.38
m˙ = 7/5.38
So mass flow m˙ = 1.301 kJ/s
Answer:
The holiday lasted for 18 days.
Explanation:
Let's assume the number of days are as following:
let the rain in the morning and lovely afternoon = X days
Clear morning and rain in the afternoon = Y days
No rain in the morning and in the afternoon = Z days
Now according to the question
Number of days with rain = X + Y = 13 days
Number of days with clear mornings = Y + Z = 11 days
Number of days with clear afternoons = X + Z = 12 days
Solving above 3 equations, we get
X = 7, Y = 6 and Z = 5
Now total number of days on holiday = X+Y+Z = 7+6+5 =18
Hence, total number of days on holiday = 18 days.