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Natalija [7]
3 years ago
14

URGENT WORTH 20 POINTS

Mathematics
1 answer:
Triss [41]3 years ago
5 0
If we were to draw a best fit line, the y-interest would be near 15, and the slope would be negative.

In the options given, the slope is either -3 or -13. If we imagine a line through the plotted points, the rise would be about 15 while the run would be about 5. This means the slope is about -3.

The best answer is y = -3x + 15





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Find the distance between the points (3, -5) and (-6, -5).
Sophie [7]

ANSWER

9

EXPLANATION

We want to find the distance between the points (3, -5) and (-6, -5).

The given points have the same y-coordinates .

This means it is a horizontal line.

We use the absolute value method to find the distance between the two points.

We find the absolute value of the distance between the x-values.

The distance between the two points is

|3--6|=|3+6|=|9|=9

8 0
3 years ago
P(5,3); y=4x<br><br>if you help me I will be thankful forever pls
horrorfan [7]
Y= -1/4x + 4.25, perdendicular then it must be the opposite of 4x which is -1/4. Then you multiply it with 5 and then add or subtract a number so you can find 3. So -1/4× 5 + 4.25= 3. Here you gooo!
6 0
3 years ago
a rope that measures 3.98 meters is cut into two pieces. if one peice measures 1.425 meters, what is the length of the other pie
Anna11 [10]
The length of the other piece is 2.555
8 0
4 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
3 years ago
Which of the following points lies on the graph of y=x^2-5?
grandymaker [24]

Answer:

(3, 4)

Step-by-step explanation:

6 0
3 years ago
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