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3 years ago

Simplify 4.2(2x − 0.5y) − 2(4.1x − 0.3y)

2 answers:

8 0

Multiplying 4.2 with the value was given in the bracket, then multiply -2 with the values given in the bracket,we get [8.4x - 2.1y - 8.2x + 0.6y]
then we simply the x and y terms, and the answer is [0.2x - 1.5y]

hope this helped!!

KonstantinChe [14]3 years ago

6 0

Answer:

0.2 1.5

Step-by-step explanation:

no problem

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James bought 6 cupcakes and a pint of ice cream. He knows his total bill and the pint of ice cream was $5.76, but

PilotLPTM [1.2K]

Answer:

Each cupcake was $2.75

Step-by-step explanation:

We subtract the price of the ice cream from the total bill $22.26-$5.76=$16.50

We know he only bought the ice cream and cupcakes so once we subtracted the price of the ice cream, we now have the price of the cupcakes all together only

We divide the price of all the cupcakes by the amount of cupcakes to get the price of each individual cupcake $16.50/6=$2.75

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3 years ago

Suppose y varies directly with x. If y=6 when y=-2, find x when y=15.

raketka [301]

Answer:

-5

Step-by-step explanation:

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3 years ago

The sum of six fifths 6 5 and six timessix times a number is equal to four fifths 4 5 subtracted from seven timesseven times the

maw [93]

Answer :

The required number is 2.

Step-by-step explanation:

Given : The sum of six fifths and six times a number is equal to four fifths subtracted from seven times the number.

To find : The number ?

Solution :

Let the number be 'x'.

The sum of six fifths and six times a number i.e. $\frac{6}{5}+6x$

Four fifths subtracted from seven times the number i.e. $7x-\frac{4}{5}$

According to question,

$\frac{6}{5}+6x=7x-\frac{4}{5}$

$7x-6x=\frac{6}{5}+\frac{4}{5}$

$x=\frac{10}{5}$

$x=2$

The required number is 2.

5 0

3 years ago

The circumference of a circle is 16π cm. What is the area, in square centimeters? Express your answer in terms of \piπ.

zepelin [54]

Answer:

64 pi

Step-by-step explanation:

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4 0

4 years ago

Read 2 more answers

Determine whether the graph of the equation is symmetric with respect to the y-axis, the x-axis, the origin, more than one of th

Murrr4er [49]

$\bf x^2y^2+3xy=1\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for x-symmetry}}{y=-y}}{x^2(-y)^2+3x(-y)=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\$

$\bf \stackrel{\stackrel{\textit{test for y-symmetry}}{x=-x}}{(-x)^2y^2+3(-x)y=1}\implies x^2y^2-3xy=1\impliedby 
\begin{array}{llll}
\textit{function differs}\\
\textit{from original}\\
\textit{no dice}
\end{array}\\\\
-------------------------------\\\\
\stackrel{\stackrel{\textit{test for origin-symmetry}}{x=-x~~y=-y}}{(-x)^2(-y)^2+3(-x)(-y)=1}\implies x^2y^2+3xy=1\impliedby 
\begin{array}{llll}
origin\\symmetry
\end{array}$

so, recall, the function has symmetry when the yielded resulting function resembles the original function, after negativizing the variable(s).

Also recall that minus*plus is minus, and minus*minus is plus.

7 0

4 years ago