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kiruha [24]
3 years ago
10

I need help with science o.o:

Physics
2 answers:
Monica [59]3 years ago
8 0

Answer:

1.true

2true

3.false

Explanation:

espero que te ayude

Nikolay [14]3 years ago
6 0

Answer:

  1. True
  2. True
  3. False

Explanation:

this is the answer

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Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Recor
s344n2d4d5 [400]

Answer:

Detailed explanation:

Density of water=1000kg/m³

Hence mass of water displaced is:

m=d×v

=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)

=4.3 kg of water

Hence, mass of football is also 4.3 kg(Archimedes principle)

Thus density of football

=mass÷volume

substitute the mass and volume and solve.

hope this helps

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Which is an example of a chemical change? A) glass melts in a furnace B) liquid water boils into steam C) newspaper decays in a
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I believe your answer is C.
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5. Relationships in a community can be cooperative or competitive.<br><br> True<br> False
VARVARA [1.3K]

Answer:

True

Explanation:

is the correct answer

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3 years ago
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What chemical reactions support all life on earth?
OlgaM077 [116]

Answer:

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5 0
3 years ago
A tank is is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9
rusak2 [61]

Answer:

3.9 × 10^7 J

Explanation:

Given that a tank is is half full of oil that has a density of 900 kg/m3. Find the work W required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r = 15 m and h = 5 m.) W = 1.59 J

Solution

Since the tank is half full, the height = 2.5m

Pressure = density × gravity × height

Pressure = 900 × 9.8 × 2.5

Pressure = 22050 Pascal

The cross sectional area of the pump will be area of a circle.

A = πr^2

A = π × 15^2

A = 706.858 m^2

Using the formula

Density = mass/volume

Mass = density × volume

Mass = 900 × 706.86 × 2.5

Mass = 1590.435

Energy = mgh

Energy = 1590.435 × 9.8 × 2.5

Energy = 38965657.8 J

Since the work done = energy

Therefore, the work done = 3.9 × 10^7 J

7 0
3 years ago
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