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Alex17521 [72]
3 years ago
5

Explain why you can multiply both the numerator and denominator by the same number

Physics
2 answers:
faltersainse [42]3 years ago
3 0

hope this help love y all!

xxTIMURxx [149]3 years ago
3 0

Explanation:

when we are multipling one number whis a number which have same numenator and denominator it will be it self

because A/A=1

a number divided by the same number is equal to 1

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Debido al desorden en el laboratorio un científico tiene 2 termómetros diferentes pero no sabe en qué escalas están por lo que d
just olya [345]

Answer:

La escala del termómetro ''A'' es grados Celsius.

La escala del termómetro ''B'' es grados Fahrenheit.

Explanation:

Para hallar en qué escalas están los termómetros partimos de que la mezcla a la cuál se midió su temperatura mantuvo su temperatura constante.

Esto quiere decir que los termómetros están expresando la misma temperatura pero en una escala distinta.

Sabemos que dada una temperatura en grados Celsius ''C'' si la queremos convertir a grados Fahrenheit ''F'' debemos utilizar la siguiente ecuación :

F=(\frac{9}{5})C+32 (I)

Ahora, si reemplazamos y asumimos que la temperatura de 18° es en grados Celsius, entonces si reemplazamos C=18 en la ecuación (I) deberíamos obtener F=64.4 ⇒

F=(\frac{9}{5}).(18)+32=32.4+32=64.4

Efectivamente obtenemos el valor esperado. Finalmente, corroboramos que la temperatura del termómetro ''A'' está medida en grados Celsius y la temperatura del termómetro ''B'' en grados Fahrenheit.

6 0
3 years ago
The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i
Archy [21]

Explanation:

Using Newtons second law on each block

F = m*a

Block 1

T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1

Block 2

T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2

Block 3

- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3

Solving Eq1,2,3 simultaneously

Divide 1 and 2

\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)}  \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} =  \frac{M_{1} *T_{2} }{M_{2} } .... Eq4

Put Eq 4 into Eq3

T_{2} = \frac{M_{3}*(g-a) }{1+\frac{M_{1} }{M_{2} } }  ...Eq5

Put Eq 5 into Eq2 and solve for a

a = \frac{M_{3}*g -u*g*(M_{1} + M_{2}) }{M_{1} + M_{2} + M_{3} }  .... Eq6

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

T_{2} = M_{2}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\T_{1} = M_{1}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\

5 0
4 years ago
What is the total translational kinetic energy in a test chamber filled with nitrogen (N2) at 2.02×105 Pa and 20.7°C? The dimens
Mumz [18]

Answer:

K. E = 6.0796 × 10^ -21 Joule

Explanation: see attachment

3 0
4 years ago
While sitting in a moving bus you throw an apple up into the air. The apple will land back into your hand.
Neko [114]
False because you have moved after you through the apple in the air
6 0
3 years ago
The heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?
nataly862011 [7]

Answer:

hey!

Your answer will be EXACTLY 113.97899 Pounds

Explanation:

BUT IF YOU ROUND THIS UP TO THE WHOLE NUMBER etc IT WILL BECOME 114 POUNDS!

Hope This Helped!

itsMATT04

3 0
4 years ago
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