Answer: 266
Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.
(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates
(2) Solve for n: 8,512 = 32n; n = 266
Answer:
x = 4
Step-by-step explanation:
Solve for x:
x - 12 + 18 = 10
Hint: | Group like terms in x - 12 + 18.
Grouping like terms, x - 12 + 18 = x + (18 - 12):
x + (18 - 12) = 10
Hint: | Evaluate 18 - 12.
18 - 12 = 6:
x + 6 = 10
Hint: | Isolate terms with x to the left hand side.
Subtract 6 from both sides:
x + (6 - 6) = 10 - 6
Hint: | Look for the difference of two identical terms.
6 - 6 = 0:
x = 10 - 6
Hint: | Evaluate 10 - 6.
10 - 6 = 4:
Answer: x = 4
11.72×60=703.2
9.66×60=579.6
((9.66÷11.72)−1)×100=−17.6%
<span>How much more will it cost Olivia if she uses the credit card instead of the personal loan?
it will cost 2,880</span>
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
