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Inessa05 [86]
3 years ago
12

2x² + 166 +30

Mathematics
1 answer:
Darya [45]3 years ago
5 0

Answer:

c....................

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How many WATTS are used in a 5 amp drill that uses 110 volts?
zimovet [89]

Calculating wattage is a quick process once you know the appliance's amperage and voltage — you simply multiply the two figures. An appliance that uses 110 volts of electricity and 5 amps uses 550 watts.

Hope this helps!

8 0
2 years ago
Identify Arithmetic Mean, Geometric Mean and Harmonic Mean from the following averages: 56.4, 59.8 and 55.8
photoshop1234 [79]
If you would like to calculate the arithmetic mean, geometric mean, and harmonic mean from the following averages, you can calculate this using the following steps:

averages: 56.4, 59.8, 55.8
the number of values: 3

arithmetic mean:
(56.4 + 59.8 + 55.8) / 3 = 57.33

geometric mean:
(56.4 * 59.8 * 55.8)^(1/3) = 57.31

harmonic mean:
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7 0
3 years ago
Please help Use the expression 8a + 16c.
alexdok [17]

Answer:

C  89a + 2c)

Step-by-step explanation:

The largest factor of both 8 and 16 is 8.  So, 8 = GCF

factor out an 8 and you get 8(a + 2c)

To check if you are correct, multiply and see if you get what you started with.

3 0
3 years ago
Read 2 more answers
100 POINTS HEY YALL IS THIS LINE OF BEST FIT A LINE OF BEST FIT LOL
telo118 [61]

Answer:

try and angle it more upwards so that it goes more through the second dot from the top and those 2 dots towards the bottom of the graph above the line.

Step-by-step explanation:

8 0
2 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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