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Assoli18 [71]
3 years ago
10

A city issues 3-digit license plates for motorized scooters. The digits 0-9 are chosen at random by a computer program. What is

the probability that a license plate issued meets each set of criteria
Mathematics
1 answer:
dimaraw [331]3 years ago
7 0

Answer:

80/111

Step-by-step explanation:

For starters, since it is 3 digits inclusive of 0, from 0 - 9, then there are 1000 possible total plate combination from 000 - 999.

If no number is expected to be repeated in the combination, then there exists 10 numbers(say 0-9) for the first digit, 9 numbers(say 1-9) for the second digit and 8 numbers(1-8) for the third digit.

This means that there will be 10 * 9 * 8 total possible outcomes. Considering that the possible combinations is 999, then the probability is

10 * 9 * 8 = 720/999

And that is simplified to 80/111

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Which stem-and-leaf plot represents this data? 80, 81, 91, 92, 66, 55, 54, 30, 55, 79, 78 A stem-and-leaf plot with a stem value
Rama09 [41]

You are solving for a stem-and-leaf plot that represents the given data: 80, 81, 91, 92, 66, 55, 54, 30, 55, 79, 78.

Note that a stem-and-leaf plot is used in this way:

For example: 8|7

In this case, the stem is the tens place value, and is signified by 8. 7, on the other hand, is the ones place value. <em>Multiple leafs can share the same stem</em>. For example, a stem-and-leaf plot of 85, 86, 87, would give you 8|5 , 6 , 7.

Now, set the given data set in order:

30 , 54 , 55 ,  55 , 66 , 78 , 79 , 80 , 81 , 91 , 92

Now, create the stem-and-leaf plot:

Stem | Leaf

\left[\begin{array}{c|ccc}3&0\\5&4&5&5\\6&6\\7&8&9\\8&0&1\\9&1&2\end{array}\right]

~

Your answer will be:

A stem value of 3, with a leaf value of 0. A stem value of 5, with a leaf value of 4 & 5. A stem value of 6, and a leaf value of 6. A stem value of 7, and a leaf value of 8 & 9. A stem value of 8, and a leaf value of 0 & 1. A stem value of 9, and a leaf value of 1 & 2.

~

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2 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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