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2 years ago

Equivalent expression 7s+8t+10s+12t

Mathematics

1 answer:

Dahasolnce [82]2 years ago

4 0

Answer:

17s+20t

Step-by-step explanation:

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3k-7/5 = 16 what is does k equal?

Gnom [1K]

3k=16+7/5
3k=87/5
k=29/5

3 0

3 years ago

Find the volume of a prism whose area of base is 44cmsquare and height is22cm

vovangra [49]

For this problem, you can use the volume of a prism equation:
V=Bh
Where B is the area of the base and h is the height.

So to solve this problem, all you have to do is mutiply 44 square cm by 22 cm.
44 square cm • 22 cm = 968 cubic cm

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3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

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3 years ago

Which equation is a linear function??

Sever21 [200]

The third equation is linear

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3 years ago

15 ft

Wittaler [7]

Answer: 440 dollars

Step-by-step explanation:

3 0

3 years ago