So...that's telling you:
Y=0 at x=0 and x=2
The graph is decreasing when X is less than 1
f'(x) can not equal 0 with the previous statement.... please give the correct statement... I would assume that is is f'(1)=0, so there would be a max at x=1
f(x) is increasing when x is greater than 1
and if f''(x) is always 0, the graph is always concave downward.
Answer:
Pythagoras theorem.
hypotenuse²=height²+base²
x²=15²+12²
x²=225+144
x²=329
x=329½
x=19.20
Answer:
Right part:
where 
Step-by-step explanation:
Linear equation have no solution if it is impossible for the equation to be true no matter what value we assign to the variable x.
The left part of the equation Tomas wrote is

The right part of the equation should be of the form

where 
In this case, the equation will take look

Since
this equality is always false.
Remark: 1) If a=8, the equation
is equivalent to the equation

and the lest equation has infinitely many solutions.
2) When coefficient at x differs from
the equation has unique solution.
Answer:
(6y - 1)(6y + 1)
Step-by-step explanation:
To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square is the product of the difference of the number and the sum of the numbers.
Such that
a² - b² = (a - b) (a + b)
Hence 36y² - 1
= 6²y² - 1²
= (6y)² - 1²
= (6y - 1)(6y + 1)
M=2p over2k+1<span>Km=m/2+p. Solve for m</span>