Question

A rectangle has a perimeter of 58. The width is 7 less than the length. Find the length

Answer 1

Answer:

Length = 18 Width = 11

Step-by-step explanation:

Perimeter = 2(length) + 2(width)

So let's label the unknown length as x. Width would then be (x-7). Then plug it into the perimeter equation.

2(x) + 2(x-7) = 58

Then use PEMDAS which will give us

2x+2x-14 = 58

Combine like terms

4x -14 = 58

Add 14 to both sides

4x = 72

To get x by itself you have to divide both sides by 4.

x = 18

So length is 18 and width is (18-7) which is 11.