A rectangle has a perimeter of 58. The width is 7 less than the length. Find the length
1 answer:
Answer:
Length = 18 Width = 11
Step-by-step explanation:
Perimeter = 2(length) + 2(width)
So let's label the unknown length as x. Width would then be (x-7). Then plug it into the perimeter equation.
2(x) + 2(x-7) = 58
Then use PEMDAS which will give us
2x+2x-14 = 58
Combine like terms
4x -14 = 58
Add 14 to both sides
4x = 72
To get x by itself you have to divide both sides by 4.
x = 18
So length is 18 and width is (18-7) which is 11.
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