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Iteru [2.4K]
3 years ago
10

A and b are two positive integers such that the least prime factor of a is 3 and the least prime factor of b is 5. then calculat

e the least prime factor of (a+b).
Please answer it briefly. :)
Mathematics
1 answer:
noname [10]3 years ago
4 0
A and b are both odd numbers because their least prime factors are odd. When two odd numbers are added, their sum is even.

The least prime factor of (a+b) is the least even number: 2.

Perhaps I made that too brief for you. Let me know if you need clarification. 
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How do you solve for x in this quadratic equation?: 5x^2 – 34x + 24 = 0
wlad13 [49]
Quadratic formula
factoring
graphing 
completing the square
factoring by grouping
Rational Roots Theorem
synthetic division

Take a look at <span>5x^2 – 34x + 24 = 0.  The last term could have been the result of these different possible muliplications:  1*24, 2*12, 3*8, 4*6.  The leading term is 5, whose factors are 5 and 1.  Thus, possible rational roots would be
4/5 (the 4 is a factor of 24 and the 5 is a factor of 5) and 6/1 (the 6 is a factor of 24 and the 1 is a factor of 5).  

Using synth. div. to check whether 6 is actually a root:
     ___________________
6  /    5      -34          24
                  30         -24
    ------ --------------------------
         5       -4             0

since the remainder is 0, we can safely call 6 a "root."  
Note the remaining coefficients, 5 and -4:  

They correspond to the factor 5x - 4.  If we set this difference = to 0, and solve for x, we get  x = 4/5 (which is correct).

The roots of </span><span>5x^2 – 34x + 24 = 0  are  x = 4/5 and x= 6/1.</span>
5 0
4 years ago
What is 0.685 in expanded notation
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8 0
4 years ago
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Find the area of the following circle. Use = 3.14 r = 6 yd. a = square yards.
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 round the answer if needed.

5 0
3 years ago
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Reil [10]
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</span>
And now, we have f(x)=(7x-m):(2-1/3x)= (14x-2m): (6-x)

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Conclusion m=35 and n=1/3</span>
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4 years ago
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igor_vitrenko [27]
Based off of  what I can see in the  photo (its too blurry to know for sure) and what I think you're asking:

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