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Burka [1]
3 years ago
6

Find the area of the following circle. Use = 3.14 r = 6 yd. a = square yards.

Mathematics
2 answers:
olganol [36]3 years ago
8 0

Answer:

a = 113.04 square yards.

Step-by-step explanation:

We know that,

Area of circle = \pi r^{2}, where 'r' is the radius of the circle.

As, the radius given is 6 yards.

Thus, we have,

Area of circle, a = \pi r^{2}

i.e. Area of circle, a = 3.14\times 6^{2}

i.e. Area of circle, a = 3.14 × 36

i.e. Area of circle, a = 113.04 square yards.

Thus, the area of the circle i.e. a = 113.04 square yards.

Liono4ka [1.6K]3 years ago
5 0
Area = PI x r^2

area = 3.14 x 6^2
area = 3.14 x 36

area = 113.04 square yards
 round the answer if needed.

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4 years ago
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Answer:

<u>18.8%</u>

Step-by-step explanation:

For calculating this, focus on one part of the table :

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There are 32 students who do not like sandwiches, and 6 of them do not like pies. Take this a proportion :

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7 0
2 years ago
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The population of a country was increased in the past 4 years. The annual presentage increases are 20%,25%,30%,10% respectively.
Vladimir79 [104]

The answer is 114.5%.

Let the original population be denoted by x.

Now, let's go through the percentage increase per year.

<u>Year 1</u>

  • x (1 + 20%)
  • x (1.2)
  • 1.2x

<u>Year 2</u>

  • 1.2x (1 + 25%)
  • 1.2x (1.25)
  • 1.5x

<u>Year 3</u>

  • 1.5x (1 + 30%)
  • 1.5x (1.3)
  • 1.95x

<u>Year 4</u>

  • 1.95x (1 + 10%)
  • 1.95x (1.1)
  • 2.145x

Overall increase : 214.5% - 100% = 114.5%

Hence, the overall percentage increase in these 4 years is 114.5%.

7 0
2 years ago
(5,-6) after a rotation of 90 digres
vlada-n [284]

Answer:

depends which way you rotate it

Step-by-step explanation:

counterclockwise rotation: (6,5)

clockwise rotation: (-6,-5)

7 0
3 years ago
Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.
il63 [147K]

Answer:

The minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

Step-by-step explanation:

Given function is f(x) = 0.15(x + 1)^2 - 3

We need to find the maximum value or the minimum value for the function.

Now, differentiate f(x) = 0.15(x + 1)^2 - 3  w.r.t x.

f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\

f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)

Now, we will equate f'(x)=0 to find critical point.

0.3(x+1)=0\\x=-1

Plug this critical point in to the function f(x) = 0.15(x + 1)^2 - 3  we get,

f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3

Also, f''(x)=0.3 which is positive, We have minimum value.

So, the minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

7 0
3 years ago
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