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3 years ago

Hello can anyone help with this?

Mathematics

1 answer:

Ray Of Light [21]3 years ago

3 0

Answer:

<2 and <13 are alternate exterior angles.

In simple form, alternate exterior angles are the opposite angle on the opposing parallel line. So, to make you understand better, <4 and <15 are alternate exterior angles.

Hope this helps :D

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Which equation has infinitely many solutions? A) 4x + 3 3 = 4x + 5 B) 10x + 8 2 = 5x + 4 C) 8x − 5 3 = 2x − 2 D) 8x − 5 2 = 4x −

abruzzese [7]

Answer: If the left side and the right side of the equation are equal, the equations has infinitely many solutions.

Step-by-step explanation:

The options are not clear, so I will give you a general explanation of the procedure you can use to solve this exercise.

The Slope-Intercept form of the equation of a line is the following:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

For this exercise you need to remember that, given a System of Linear equations, if they are exactly the same line, then the System of equations has Infinitely many solutions.

If you have the following system:

$\left \{ {{y=2x+1} \atop {y=\frac{12}{6}x+1}} \right.$

You can simplify the second one:

$y=2x+1$

Then, both equations are the same line.

By definition you can also write the systemf making both equations equal to each other:

$2x+1=2x+1$

So, if the left side and the right side are equal, the equations has infinitely many solutions.

3 0

3 years ago

How do you turn 800/100 in decimal form

Delvig [45]

<span>800 % = 8.00 or 800/100 or 8/1
800 is bigger than 100, so 8 would go before the decimal! </span>

6 0

3 years ago

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if there was for 4 fishes in the fish tank on two of the fishes died. how many fishes are in the fish tank

Keith_Richards [23]

There are two fish left.

4 0

4 years ago

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-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4

umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

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3 years ago

In a poll of travelers, 85% said that traveling by air makes them nervous, and 450 travelers said that it does not make them ner

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The answer is 1,338 were polled

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3 years ago

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