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Jet001 [13]
3 years ago
14

HOW DO YOU FIND THE ARC OF A CIRCLE????

Mathematics
1 answer:
padilas [110]3 years ago
6 0

Answer:

1. Multiply the area by 2 and divide the result by the central angle in radians.

2. Find the square root of this division.

3. Multiply this root by the central angle again to get the arc length.

Step-by-step explanation:

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Answer me pleaseeee..... prime numbers between 1 to 10 ?​
My name is Ann [436]

Answer:

2, 3, 5, 7

Step-by-step explanation:

prime numbers between 1 to 10 are 2,3,5,7. it's very easy. 1 is not prime number because it behave as both prime and composite.

8 0
2 years ago
A fruit stand has to decide what to charge for their produce. They need \$10$10dollar sign, 10 for 4 apples and 4 oranges. They
Lostsunrise [7]

Answer:

  no

Step-by-step explanation:

The prices are inconsistent, so there is no unique price that can be set for either an apple or an orange that will give the total prices indicated.

__

The first relation can be written as ...

  $10 = 4A +4O

  $10 = 4(A +O) . . . . factor out 4

  $2.50 = A +O . . . . divide by 4

The second relation can be written as ...

  $12 = 6A +6O

  $12 = 6(A +O) . . . . factor out 6

  $2 = A +O . . . . . . . divide by 6

These two relations give different prices for 1 apple and 1 orange. There is no price that can be set for either fruit that will give this result.

No unique prices can be assigned.

7 0
2 years ago
How is the graph of y=x^2 different from the graph of y=x^2-2
Zinaida [17]
It is two units shifted downwards. you can see it by substituting x=0 for both equations
5 0
3 years ago
Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6
Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

5 0
3 years ago
Find m∠H. Put the answer below.<br> m∠H =
max2010maxim [7]

Answer:

30 degrees

Step-by-step explanation:

This is the third time I am answering the same question asked by you.

5 0
2 years ago
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