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ale4655 [162]
4 years ago
8

What processes are adding additional carbon dioxide to the atmosphere?

Chemistry
1 answer:
gtnhenbr [62]4 years ago
7 0

Answer:

Explanation:

When animals breathe or decompose (decay), carbonate rocks weather, forest fires ignite, and volcanoes erupt, carbon dioxide is released into the atmosphere naturally. Human practices such as the combustion of fossil fuels and trees, as well as the manufacture of cement, contribute carbon dioxide to the atmosphere.

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How many valance are transferred from the nitrogen atom to potassium in the formation of the compound potassium nitride?
never [62]
3 valence electrons are transferred in the formation of the compound potassium nitride because nitrogen needs 3 valence electron to become stable, or to have the electron configuration of noble Gases. 
5 0
3 years ago
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Which of the following structures surround cells?
8090 [49]
Cells are surrounded by #2 , Cell membrane and Cell wall thats what protects the cell
4 0
3 years ago
Diffrentiate the reactivity of metals and Non-metals with air / oxygen.​
algol13

Answer:

Both metals and non-metals when burnt in oxygen form their oxides. Oxides of metals are basic in nature and oxides of non-metals are acidic in nature.

8 0
2 years ago
How can you explain therma expansion in terms of kinetic energy ? please help
nata0808 [166]

Answer:  

Heat causes the molecules to move faster (heat energy is converted to kinetic energy), which means that the volume of a solid or a liquid. ... The particles in the air do not have more kinetic energy than particles in the mercury, because they are the same.

Explanation:

I hope this help you!

7 0
3 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
nikdorinn [45]

Answer:

2.1x10⁹ years

Explanation:

U-238 is a radioactive substance, which decays in radioactive particles. It means that this substance will lose mass, and will form another compound, the Pb-206.

The time need for a compound loses half of its mass is called half-life, and knowing the initial mass (mi) and the final mass (m) the number of half-lives passed (n) can be found by:

m = mi/2ⁿ

The mass of Pb-206 will be the mass that was lost by U-238, so it will be mi - m. Thus, the mass ration can be expressed as:

(mi-m)/m = 0.337/1

mi - m = 0.337m

mi = 1.337m

Substituing mi in the expression of half-life:

m = 1.337m/2ⁿ

2ⁿ = 1.337m/m

2ⁿ = 1.337

ln(2ⁿ) = ln(1.337)

n*ln(2) = ln(1.337)

n = ln(1.337)/ln2

n = 0.4190

The time passed (t), or the age of the sample, is the half-life time multiplied by n:

t = 4.5x10⁹ * 0.4190

t = 1.88x10⁹ ≅ 2.1x10⁹ years

5 0
3 years ago
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