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Ierofanga [76]
3 years ago
14

What’s the fastest way to balance chemical equations

Chemistry
1 answer:
Anon25 [30]3 years ago
6 0

Hey there!

The best way to balance chemical equations is to first start by balancing polyatomic ions such as OH and SO₄.

Next, balance other elements, but save elements that are by themselves for last, such as H₂ or Fe. Once you balance everything else you can do the ones by themselves, it's much easier.

Hope this helps!

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Going from a solid phase to the gas phase without passing through the liquid phase is called
svetoff [14.1K]

Deposition is the answer you are looking for :)

8 0
3 years ago
If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres, what is the volume of the gas?
iVinArrow [24]

If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.

Explanation:

Data given:

number of moles of the gas = 0.725

temperature = 105 K

pressure = 3.75 atm

volume of the gas =?

R = 0.08206 Latm/mole Kelvin

Applying the ideal gas law to calculate the volume of the given gas:

PV = nRT

rearranging the equation to calculate volume:

V = \frac{nRT}{P}

putting the values in the equation:

V = \frac{0.08206 X 0.725 X 105}{3.75}

V = 1.66 Litres.

At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.

6 0
3 years ago
Write and balance the chemical equation for the reaction associated with ΔHof of Li3N(s). What is the sum of all of the coeffici
ivann1987 [24]

Explanation:

In this reaction, the reactants are Li and N2. The product is Li3N

So we have;

Li + N2 → Li3N

Upon balancing, we have;

6Li + N2 → 2 Li3N

The sum of the coefficients is 6 + 1 + 2 = 9

5 0
3 years ago
Provide a method for separating the mixtures of two or three compounds, dissolved in a solvent diethyl ether. In each case one o
lys-0071 [83]

Answer:

The complete aerobic oxidation of glucose is coupled to the synthesis of as many as 36 molecules of ATP

Explanation:

Glycolysis, the initial stage of glucose metabolism, takes place in the cytosol and does not involve molecular O2. It produces a small amount of ATP and the three-carbon compound pyruvate. In aerobic cells, pyruvate formed in glycolysis is transported into the mitochondria, where it is oxidized by O2 to CO2. Via chemiosmotic coupling, the oxidation of pyruvate in the mitochondria generates the bulk of the ATP produced during the conversion of glucose to CO2. The biochemical pathways that oxidize glucose and fatty acids to CO2 and H2O.

5 0
3 years ago
The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
nevsk [136]

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

3 0
3 years ago
Read 2 more answers
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