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3 years ago

Refer to the following compounds.

Chemistry

1 answer:

goblinko [34]3 years ago

5 0

Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.

ALWAYS LOOK for the Functional Group in question.

A. Would likely not stay in water, or at least not be acidic, for it is butane gas.

B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.

C. This is an Ether. It will not give up an H+, it it not an acid.

E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.

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A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the

Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

$V_2 = \frac{P_1P_2}{P_2}$ that is V₂ = $\frac{1atm*1.32L}{90atm}$ = $\frac{11}{750}L$ or 0.01467L

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3 years ago

Read 2 more answers

What is half of 1 and 1/3 cups of semisweet chocolate?

Marina86 [1]

Answer:

2/3 cup of semisweet chocolate

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4 years ago

How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)

polet [3.4K]

Answer:

375.2 kJ

Explanation:

H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then state a rule of three:

2 mol HF -------- 536 kJ

1.4 mol HF --------- X

And solve for X:

X = 1.4 mol * 536 kJ / 2 mol

X = 375.2 kJ

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3 years ago

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BaLLatris [955]

Answer:

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STatiana [176]

i is dont no

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