How to find the smallest integer k such that 60k is a perfect square
1 answer:
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Answer:
Step-by-step explanation:
Notice that is a right triangle where its hypotenuse is
. We can also see that
. For this we must use the Pythagorean Theorem.
Recall:
The Pythagorean Theorem states that if you have a right triangle, the principal square root of the sum of the squares of each leg is the length the hypotenuse.
We can see that and
Answer:
1a. 8
1b. AB & BC
1c. AC
2. miles
3. NO
Step-by-step explanation:
1a. AC is your hypotenuse which is C² and BC is B², so we plug it in the equation.
A²+6²=10²
A²+36=100
A²=64
A=
A=8
1b. Legs are the two shorter sides, AB & BC, which are 6 & 8 respectively.
1c. The hypotenuse is the longest side AC
2. Make lines that make the graph for a triangle with a line. My graph is linked below. Then counts the points, AC=6, BC=4, then use the pythagorean therom.
6²+4²=X²
36+16=52
=X
3. 15²+17²=19²
514=361
not possible
so it is not a right triangle