Question

5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue

Answer 1

Answer:

$\lambda=451nm$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

$E=\frac{hC}{\lambda }$

Thus, we solve for the wavelength as shown below:

$\lambda=\frac{hC}{ E}$

And finally plug in the energy, Planck's constant and speed of light to obtain:

$\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm$

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