Ignore my writing answer is in pictute
Answer:
i) pH = 2
pH = -log(H+)
:- (H+) = 10^(-2)
:- (H+) = 0.01 M
ii) pH = 6
pH = -log(H+)
:- (H+) = 10^(-6)
:- (H+) = 0.000001 M
Explanation:
By definition: pH = -log(H+).
Given your pH, solve for the H+ using the the following log rule:
if a = (+/-) log (b) then
b = 10^((+/-) a).
Also remember unit of concentration is molar (M)
Answer:
The answer will be Ligand A with a dissociation constant (Kd) of
M
Explanation:
When the dissociation constant in the ligand is small (in order of nano) (
) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.
On the other hand, the occupancy percentage of the ligand does not imply binding. Conversely, a High-affinity ligand binding with the proteins implies that a relatively low concentration of a ligand is adequate to occupy the maximum ligand-binding site.
Explanation:
The given reaction is as follows.

Value of equilibrium constant is given as
= 4.3 \times 10^{6}[/tex].
Concentration of given species is
= 0.010 M;
= 10.M;
= 0.010 M.
Formula for experimental value of equilibrium constant (Q) is as follows.
Q =
Putting the given concentration as follows.
Q =
Q = 
Q = 
It is known that when Q >
, then reaction moves in the backward direction.
When Q <
, then reaction moves in the forward direction.
When Q =
, then reaction is at equilibrium.
As, for the given reaction Q >
then it means reaction moves in the backward direction.
Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.
B . microscope
this is the answer .