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Anton [14]
4 years ago
9

How many significant figures are in 0.08260 L? 4 5 6

Chemistry
2 answers:
mars1129 [50]4 years ago
6 0

Answer:

5

Explanation:

Count the digits after the first non zero number, any number after that (even zero) counts.

Hope that helped!!! k

Anni [7]4 years ago
5 0

Answer:

\boxed{4}

Explanation:

\sf Leading \ zeros \ are \ not \ significant.

\sf Trailing \ zeros \ are \ significant.

\sf Non\  zeros \ are \ significant.

0.08260 \sf  \ has \ 4 \ significant \ figures.

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Answer:

location on the periodic table

Explanation:

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3 years ago
The 2 forces that act on atoms are the electromagnetic force and the strong nuclear force.
dolphi86 [110]

Electromagnetic forces occur between electrons and protons while nuclear forces occur between neutrons and protons in the nucleus.

Electromagnetic forces are the forces that are responsible for the attraction between electrons and protons. The electrons in shells repel each other.

The existence of electromagnetic forces explain why positively charged protons repel each other in the nucleus and neutrons are needed to buffer this effect.

The electromagnetic force has a short range. The strong nuclear force applies to the nucleus and focuses on the neutron - proton ratio.

An atom is unstable if it has too many protons because their repulsive force will exceed the nuclear force that keeps them together. Nuclear force is stronger for lighter nuclei than heavier ones.

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3 years ago
A sample of 2.45g aluminum oxide decomposes into 1.3g of aluminum and 1.15g of oxygen. What is the percentage composition of the
Vitek1552 [10]

Answer:

%Al = 53.1%%

%O = 46.9%

Explanation:

If we know the grams of a chemical compound in a specific reaction, it is possible to know the percentage of each atom that composes it.

For the Aluminum Oxide in this problem, we know its total weight and the grams of each component.

therefore we can determine the percentage ratio of its components through:

For Al

%Al = \frac{mass of Al}{mass of Aluminium oxide} . 100%

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In the same way for oxygen

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What describes the pool of electrons in metallic bonding?
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