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3 years ago

how does the structure of atoms (i.e. protons, neutron, and electrons) affect the electric charge of an object or substance.

1 answer:

8 0

Electrons contribute greatly to the atom's charge, as each electron has a negative charge equal to the positive charge of a proton. Scientists define these charges as “+1” and “-1. ” In an uncharged, neutral atom, the number of electrons orbiting the nucleus is equal to the number of protons inside the nucleus.:

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____Fe2O3 + ___H2O --> ___Fe(OH)3

Novosadov [1.4K]

Answer:

Fe2O3 + __3_H2O --> __2_Fe(OH)3

Explanation:

____Fe2O3 + __3_H2O --> __2_Fe(OH)3

Fe -2 Fe -2

H - 6 H - 6

O - 6 O- 6

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3 years ago

Can anyone Please do this for me???I am trying to help my son with his Chemistry and I don't understand it. I have read the text

alina1380 [7]

Number 1 do a data table on paper and do as it was said, then go into Microsoft Excel and put your chart in. For 2 make a line graph(as stated) and do what it tells you.For 3 do as said with the line graph or whatever it should look somewhat like a math chart(the coordinate plane) and do as said. For number 4 help him/her study the charts and analyze the difference between the two. And for number 5 make him/her choose one element and research and write down the questions.

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3 years ago

Read 2 more answers

Explain how a graphical analysis can be used to explore the relationship between any two scientific variables.

noname [10]

A graphical analysis can be used to explore the relationship between any two scientific variables by showing numerical data through a graph, which is an easier and more vivid way to interpret results, compared to reading a table of numbers.

4 0

3 years ago

How many liters in 2.20 mol of hydrogen gas?

Papessa [141]

Answer:

es el gas que respiras y despues mueres

7 0

3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Tomtit [17]

Answer : The concentration of $COF_2$ remains at equilibrium will be, 0.37 M

Explanation : Given,

Equilibrium constant = 4.90

Initial concentration of $COF_2$ = 2.00 M

The balanced equilibrium reaction is,

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

Initial conc. 2 M 0 0

At eqm. (2-2x) M x M x M

The expression of equilibrium constant for the reaction will be:

$K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}$

Now put all the values in this expression, we get :

$4.90=\frac{(x)\times (x)}{(2-2x)^2}$

By solving the term 'x' by quadratic equation, we get two value of 'x'.

$x=1.291M\text{ and }0.815M$

Now put the values of 'x' in concentration of $COF_2$ remains at equilibrium.

Concentration of $COF_2$ remains at equilibrium = $(2-2x)M=[2-2(1.219)]M=-0.582M$

Concentration of $COF_2$ remains at equilibrium = $(2-2x)M=[2-2(0.815)]M=0.37M$

From this we conclude that, the amount of substance can not be negative at equilibrium. So, the value of 'x' which is equal to 1.291 M is not considered.

Therefore, the concentration of $COF_2$ remains at equilibrium will be, 0.37 M

3 0

3 years ago