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Elena-2011 [213]
3 years ago
15

Which two operations will solve this equation x/4-5=1

Mathematics
1 answer:
Harman [31]3 years ago
4 0
The last or second sentence
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Help is the answer of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20-%5Cfrac%7B4%7D%7B5%7D" id="TexFormula1" title="
cestrela7 [59]

Answer:

negative

Step-by-step explanation:

1/3 - 4/5

Get a common denominator of 15

1/3*5/5 = 5/15

4/5*3/3 = 12/15

5/15 - 12/15

-7/15

4 0
4 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PLEASE PLEASE PLEASE PLEASE-
Zina [86]

Answer: The area of Figure ABCDE is 79.5 square units.

Step-by-step explanation:

<em>Triangle ABC is the top triangle of Figure ABCDE.</em>

<u>Triangle ACD is the triangle on the right of Figure ABCDE.</u>

Triangle AED is the triangle on the bottom left of Figure ABCDE.

So, we need to add <em>23.85</em>, <u>29.4</u>, and 26.25 to get the area of Figure ABCDE!

23.85 + 29.4 + 26.25 = 79.5

4 0
3 years ago
2. The line that passes through the points (-6, p)
Kobotan [32]
Answer: -26=p


Explanation: The slope formula is m=(y2-y1)/(x2-x1).

Thus, we have 6=(2-p)/(-10-(-6)).

Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.
5 0
3 years ago
1. h(2) + g(2) *<br> h(t) = 3-5<br> g(t) = 2t - 5
kap26 [50]

Answer:

h(2)+g(2) = -3

Step-by-step explanation:

h(2) +g(2)\\ \\h(t) = 3-5, g(t) = 2t -5

        Replace the variable  (t)  with (

2)  in the expression.

h (2) = 3 - 5

        Replace the variable  (t)  with (

2)  in the expression.

g(2) = 2(2) -5

        Replace the function designators in h(2) +g(2) with the actual functions.

h(t) = 3 - 5 +2 (2) ← plug h(2) into 2(t)

         Remove parentheses.

3 - 5 + 2(2)

         Multiply 2 by 2

3 - 5 + 4 - 5

         Subtract  5  from  3

.

-2 + 4 - 5

          Add -2 and 4

2 - 5

          Subtract 5 from 2

-3

7 0
4 years ago
What are the important things an 8th grader needs to know about math?
gogolik [260]
Always foucus on the teacher ask help when needed
7 0
3 years ago
Read 2 more answers
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