Question

A theater wants 2000$ and children's tickets cost 5$ and adult tickets cost 10$.What is one combination of children and adult tickets that will make 2000$

Answer 1

Answer:

One combination would be 100 adults tickets and 200 children tickets.

Step-by-step explanation:

Given:

Cost of children's ticket = $5

Cost of adult's ticket = $10

The theater wants to make $2000

To find one combination of children and adult tickets that will make $2000.

Solution:

Let us assume a combination that:

Total money made from children tickets be = $1000

Total money made by adults tickets will be = $\ 2000-\ 1000$ = $1000

Thus, number of children's tickets will be:

⇒ $\frac{total\ money\ from\ children\ tickets}{Cost\ of each children ticket}$

⇒ $\frac{\ 1000}{\ 10}$

⇒ 200

Thus, number of adult tickets will be:

⇒ $\frac{total\ money\ from\ adult\ tickets}{Cost\ of each adult ticket}$

⇒ $\frac{\ 1000}{\ 5}$

⇒ 100

Thus, one combination would be 100 adults tickets and 200 children tickets.

Answer 2

Answer:

Therefore the one  combination is

200 tickets of Children and 100 tickets of Adult.

Therefore Total Amount will be given as

$5x+10y=2000$     ..........As Required

Step-by-step explanation:

Given:

Children's tickets cost = 5$ (per ticket)

Adult tickets cost = 10$ (per ticket)

Total Amount = 2000$

Let the number of Children's Ticket be " x "

and the number of Adult's Ticket be " y "

Therefore,

Total cost for Children's Ticket will be = $5\times x$

Total cost for Adult's Ticket will be = $10\times y$

Therefore Total Amount will be given as

$5x+10y=2000$      ...........As Required

So there are many combinations to get 2000$ one of the as follow

Children's tickets cost = 1000$

∴ $5x = 1000\\x=\dfrac{1000}{5}=200\ tickets$

Adult's tickets cost = 1000$

$10x = 1000\\x=\dfrac{1000}{10}=100\ tickets$

Therefore the one  combination is

200 tickets of Children and 100 tickets of Adult.