Given:
Sample mean = 65.4
Standard deviation = 1.2
Sample size = 45
Confidence level = 99%
To find:
The confidence interval.
Solution:
The formula for confidence interval is
where, 
is sample mean, z* is confidence value, s is standard deviation and n is sample size.
Confidence value or z-value at 99% = 2.58
Putting the given in the above formula, we get
Therefore, the correct option is D.
Answer:
Step-by-step explanation:
There are four values 46, 51, 53, 59
we have to draw 2 sampler with replacement
sampler median samler median
46.46 46 53.46 49.5
46.51 48.5 53.51 52
45..53 49.5 53.53 53
46.59 52.5 53.59 56
51.46 48.5 59.46 52.5
51.51 51 59.51 55
51.53 52 59.53 56
51.59 55 59.59 59
sampling distribution of the median
median probability
46 1/16
48.5 2/16
49.5 2/16
52.5 2/16
51 1/16
52 2/16
55 2/16
53 1/16
56 2/16
59 1/16
Answer:
x=(3u)/(10y)
Step-by-step explanation:
Answer:
the answer is confusing but you have to put it in as an equation and get and answer then you simplify that answer into a number sequence by rounding and estimating
Step-by-step explanation:
<h2>
Answer:</h2>
<h2>Step-by-step explanation:</h2>
<h2>Given :</h2>
<h2>To Find :</h2>
<h2>Solution :</h2>
We have to add 1 in numerator and -10 in denominator because
![\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cfrac%7B8%7D%7B101%7D%20%2C%20%5Cfrac%7B9%7D%7B91%7D%20%2C%20%5Cfrac%7B10%7D%7B81%7D%20%2C%20%5Cfrac%7B11%7D%7B71%7D%20...%5BGiven%5D)
The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.
