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Juliette [100K]
3 years ago
15

How much work is done when you push a table with 300 N of force 5 m across a room?

Physics
1 answer:
pantera1 [17]3 years ago
5 0
To answer this you multiply the N (which is 300 in this case) by m (or 5). This will give you 1500
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How is meiosis like binary fission?​
borishaifa [10]
Miosis is simair to mitosis that create gamtetes and zyotes together
5 0
4 years ago
A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket
Novay_Z [31]

To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

t = 8s, a = 165m/s^2

The velocity would be,

u = a*t \\u = 165*8\\u = 1320m/s

Now the position is,

h= \frac{1}{2} at^2

h = \frac{1}{2} 165*8^2

h = 5280m

Now with the initial speed and position found we will have the time is,

h=ut +\frac{1}{2} at^2

-5280=1320t - \frac{1}{2} 9.8t^2

4.9t^2-1320t-5280=0

Solving the polynomian we have,

t = 273.33s = 4.56minutes

Therefore  the rocket will take to hit the ground around to 4.56min

5 0
3 years ago
When running on its 11.4 V battery, a laptop computer uses 8.3 W. The computer can run on battery power for 8.5 h before the bat
AveGali [126]

Answer:

The laptop battery is capable of supplying 253980 J.

Explanation:

Given;

voltage of the battery, V = 11.4 V

power consumed by the laptop, P = 8.3 W

duration of the battery before depletion, t = 8.5 hours

Determine the amount of energy supplied by the laptop battery within 8.5 hours.

Energy, E = Power x time

Energy, E = 8.3 W x 8.5 h = 70.55 Wh

Energy, E in joules = 70.55 wh x 3600 s/h = 253980 J

Therefore, the amount of energy supplied by the laptop battery within 8.5 hours is 253980 J.

7 0
3 years ago
A particular spring has a spring constant of 25 N/m.
kotegsom [21]

Answer:

<h2>2.8×10^-3</h2>

e.p.e =  \frac{1}{2} k {x}^{2}   \\   = \frac{1}{2}  \times 25 \times (0.015m)^{2}  \\  = 0.0028125

<u>0.0028125N</u><u> </u>

8 0
3 years ago
Compare the characteristics of 4d orbitals and 3d orbitals and compared the following sentences. Check all that apply
charle [14.2K]

Answer :

<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>

<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>

Explanation :

As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.

Hence, 4d orbitals would be larger in size than 3d orbitals.

Number of nodes is any orbital is n - 1 where, n is principal quantum number.

So, number of orbital in 4d is 3.

And number of orbital in 3d is 2.

So, options (b) and (e) are correct.

8 0
3 years ago
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