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Darya [45]
3 years ago
9

Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one we

ek later?

Physics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

it should be a new moon

Explanation:

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An object experiences an acceleration of 8.5 m/s^2 over a distance of 300 m. After that acceleration it has a velocity of 400 m/
Snezhnost [94]

Answer:

393.6m/s

Explanation:

Given parameters:

Acceleration  = 8.5m/s²

Distance  = 300m

Final velocity  = 400m/s

Unknown:

Initial velocity  = ?

Solution:

To solve this problem, we use the expression below;

             v² = u²  + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

      So;

               v²  - 2as = u²

        u²   = v²   - 2as

        u²  = 400²   - (2 x 8.5 x 300)  

         u   = 393.6m/s

7 0
3 years ago
Read 2 more answers
Describe how positive and negatives pairs will react?
oksian1 [2.3K]
Positive will react better together. But opposites will try to get as far away as possible.
6 0
3 years ago
How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
DedPeter [7]

Answer:

100 Watts

Explanation:

<u>These equations are needed to work out the answer:</u>

  • power= work done/ time taken
  • work done= force* distance
  • force= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

7 0
3 years ago
Tech A says that some electric actuators are positioned by an A/C ECU which checks the air flow with sensors. Tech B says that e
Svetradugi [14.3K]

Answer:

Tech B

Explanation:

The control of electric actuators may be through through a two-wire or a five-wire circuit through the driver circuit by bidirectionally controlling via the motor wire polarity. The door position is determined by counting the actuator commutator pulses by the control module in the actuator with 2-wire, while the actuator with 5-wire uses potentiometer feedback.

The A/C ECU is the Air Condition Engine Control Unit.

7 0
3 years ago
Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
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